x^-6y^4/(-3x^2)^-4y^-1

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Solution for x^-6y^4/(-3x^2)^-4y^-1 equation: 


D( x )

-3*x^2 = 0

(-3*x^2)^-4 = 0

x = 0

-3*x^2 = 0

-3*x^2 = 0

-3*x^2 = 0 // : -3

x^2 = 0

x = 0

(-3*x^2)^-4 = 0

(-3*x^2)^-4 = 0

1/81*x^-8 = 0 // : 1/81

x^-8 = 0

x naleu017Cy do O

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((x^-6*y^4)/((-3*x^2)^-4))*y^-1 = 0

81*x^2*y^3 = 0 // : 81*y^3

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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